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∫xE^ArCtAnx/(1+x^2)^3/2Dx 次方 求解啊,知道是换...

你好 令arctanx=t,则x=tant,dx=sec²tdt ∫xe^arctanx/(1+x^2)^3/2dx =∫tante^t/(1+tan^2;t)^3/2*sec²tdt =∫tante^t/sec ³t sec ²tdt =∫tante^t/sectdt =∫sinte^tdt (1) =-∫e^tdcost =-coste^t+∫coste^tdt =-coste^t+sinte^...

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